如何將結構的實例添加到另一個結構的數組中？

嗨，我對 Solidity 很陌生。我正忙於一個記錄有關牛的各種資訊的項目。

在我下面的程式碼中，我的牛結構有一個 CattleHealth 和 CattleGrowth 數組，它們應該保存執行檢查的記錄。現在在我的 RecordHealth 和 RecordGrowth 函式中，我打算用時間戳記錄資訊並將其作為單個記錄添加到相應的數組中。

但是，我意識到我可能在使用記錄地址時犯了一個大錯誤，因為這會在每次輸入時覆蓋資訊（如果我錯了，請糾正我）。那麼如何添加單獨的記錄並將其連結到正確的奶牛/公牛？

contract WagyuRecordContract
{
   address farmer;

   struct Cattle
   {
       address RFID;
       string Name;
       uint256 Weight;
       string Gender;
       string Colour;
       string Breed;
       uint Age; 
       uint DOB;
       string Location;
       bool Parent;
       string SireName;
       string DamName;
       bool Active;
       bool ForSale;
       CattleHealth[] HealthRecord;
       CattleGrowth[] GrowthRecord;
       CattleMovements[] MovementsRecord;
   }

   struct CattleHealth
   {
       uint DateRecorded;
       string BodyCondition;
       string HealthStatus;
       string Medication; 
   }

   struct CattleGrowth
   {
       uint DateRecorded;
       uint256 FoodIntake;
       uint256 Growth;
   }

   struct CattleMovements
   {
       string From;
       string To;
   }

   mapping (address => Cattle) public cattle;
   mapping (address=> CattleHealth) public health;
   mapping (address=> CattleGrowth) public growth;

   modifier Farmer() 
   {
       require(msg.sender == farmer);
       _;
   }

   function addNewCattle(address rfid, string _name, uint _weight, string _gender, string _colour,
   string _breed, uint _age, uint _dob) Farmer public
   {
       cattle[rfid].Name = _name;
       cattle[rfid].Weight = _weight;
       cattle[rfid].Gender = _gender;
       cattle[rfid].Colour = _colour;
       cattle[rfid].Breed = _breed;
       cattle[rfid].Age = _age;
       cattle[rfid].DOB = _dob;
   }

   function NewCattleDetails(address rfid, bool _parent, string _location, string _sireName, string _damName, bool _active, bool _forSale) public Farmer
   {
       cattle[rfid].Parent = _parent;
       cattle[rfid].Location =_location;
       cattle[rfid].SireName = _sireName;
       cattle[rfid].DamName =_damName;
       cattle[rfid].Active = _active;
       cattle[rfid].ForSale = _forSale;
   }

   function RecordHealth(address rfid, string _bodyCond, string _healthStat, uint256, string _med) Farmer public
   {
       health[rfid].DateRecorded = now;
       health[rfid].BodyCondition = _bodyCond;
       health[rfid].HealthStatus = _healthStat;
       health[rfid].Medication = _med;
       cattle[rfid].HealthRecord.push(health[rfid]);
   }

   function RecordGrowth(address rfid, uint256 _foodIntake, uint256 _growth) Farmer public
   {
       growth[rfid].DateRecorded = now;
       growth[rfid].FoodIntake = _foodIntake;
       growth[rfid].Growth = _growth;
       cattle[rfid].GrowthRecord.push(growth[rfid]);
   }
  }

是的，你是對的，你只會保留最後的成長和健康記錄。我認為您可以刪除這兩行：

mapping (address=> CattleHealth) public health;
mapping (address=> CattleGrowth) public growth;

而是在以下位置創建記錄：

CattleHealth[] HealthRecord;
CattleGrowth[] GrowthRecord;

使用push()方法。

引用自：https://ethereum.stackexchange.com/questions/58816